Open B>15 INT Ragged Yellow Cape for 2.5bil, Price Negotiable

Bump

 

The way I see it 23 int raggedy is perfect

 

Could you please explain your reasoning?

 

+3 int on first slot, then 4 chaos scroll that are +5 each.

 

Well, yeah. I would consider that absolute perfection, but that’s unrealistic. Normal perfection would just be all 10%/30% scrolls.

I’ve done calculations like this before, but this type of scrolling method is near impossible. I first assumed he mistakingly thought I was buying a YAC with the first scroll being +3 int, +5 int for with Chaos Scroll on second, and +3 int for the rest.

Going by what you’re saying is why players don’t scroll 33 Atk BWG and normally only settle for 21 ATT or 23 ATT for almost 99.99% of the time.

Calculating for an absolute perfect 33 ATT BWG, the probability would be a 0.00000079008287% success rate, which is nearly impossible. That’s roughly scrolling 126,568,997 BWG from scratch to make one successful 33 ATT. You’d have to be a duper to save your last progress multiple times of your incomplete perfect glove to scroll over and over again. This was what one of the infamous dupers on GMS did, but even he didn’t go for this kind of perfection. All he went for was normal perfection for all kinds of gear like 27 ATT VSS, 26 ATT SCG and etc. There were Golden Hammers, so 26 ATT SCG was possible from the 2 extra slots.

To get a sense of how hard it is to scroll this, assuming that the online population is ~1000, every single player in the game would have to scroll and discard all the failed ones ~126,569 times to collectively produce a single 33 ATK BWG. I’m assuming ~1000 because this is what I normally see when I get on, and some players may have multiple clients opened.

 

whats the probability of hitting off +5 of a cs?

 

~5.4545454545455%

Even scrolling a Raggedy would be difficult with your suggested outcome of 23 Int, and that only has 5 slots compared to a BWG’s 7 slots.

That would be a 0.0002655556314%. Chances are a lot better, but still, no one in this game would have the funds to make this.

 

Where did u came up with the number 5%?
Possible outcomes are -5 -4 -3 -2 -1 0 1 2 3 4 5 so i suppose the p(+5|cs=pass) = 1/11 given the outcomes are equally distributed?

 

That 1/11 is within the 60% chance the scroll actually passed. 60 / 11 is where you'll find the 5.45% for each of those outcomes

 

oh now i see, well if u had one 8int 3 slot id ws it but whatever

 

The odds are still the same. Even if you use a ws, chaos scroll still has the 40% chance of failing. So you'd have:
5.45% * 11 of +/- 0-5 (adds up to 60)
40% cs fails (but slot preserved if you use ws)

But yeah, ws would change the cumulative odds of getting all 4 to pass +5, but even then, those odds are very low

 

Well, now you see why players never mention absolute perfection, because it unattainable. They consider perfect as using all 10%/30%.

 

i think what u shld do to prove these people wrong now is to get an item to tat stat

 

Math is absolute.

 

Bump

 

Bump

 

Bump

 

Bump

 

Bump

 

Bump